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6-2x-4.9x^2=0
a = -4.9; b = -2; c = +6;
Δ = b2-4ac
Δ = -22-4·(-4.9)·6
Δ = 121.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{121.6}}{2*-4.9}=\frac{2-\sqrt{121.6}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{121.6}}{2*-4.9}=\frac{2+\sqrt{121.6}}{-9.8} $
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